When 2.56 g of sulphur is dissolved in 100 g of `CS_(2)`, the freezing point of the solution gets lowerd by 0.383 K. Calculate the formula of sulphur `(S_(x))`. [Given `K_(f)` for `CS_(2)`=`3.83` `K kg mol^(-1)]`, [Atomic mass of sulphur=32g `mol^(-1)`]

Answer

`S_(s)`

Explanation

`M_(B) = (3.82 xx 2.56xx 1000)/(1000 xx 0.383) = 256`
If formula of sulphur is `S_(x)`
`32 xx x = 256 " " therefore" "x = 8`
Molecular formula ` = S_(8)` .