Calculte the osmotic pressure of a solution obtained by mixing 100 mL of 4.5% solution of urea (mol. Mass =60) and 100 mL pf 3.42% solution of cane sugar (mol. Mass =342) at 300 K. `(Given R=0.0821 L atm K^(-1) mol^(-1))`

Answer

4.20 atm.

Explanation

Total volume after mixing ` = 100 + 100 = 200 cm^(3)`
` = 0.2 L`
`pi ("urea") = (1.5 xx 0.082 xx 293)/(60 xx 0.2) = 3.0 atm`
`pi ("sugar") = (3.42 xx 0.082 xx 293)/(342 xx 0.2) = 1.20 atm `
`pi ("solution") = 3.0 + 1.2 = 4.2 atm`