KBr undergoes 80% dissociation in its 0.5M aqueous solution.Calculate the osmotic pressure of this solution at `287^(@)C`.

Answer

`22.167 atm`

Explanation

KBr dissociates as
`KBr to K^(+) + Br^(-)`
If `alpha` is the degree of dissociation , then
`alpha = (i-1)/(m-1)`
m = 2 , `alpha = 80% = 0.80`
` 0.80 = (i-1)/(2-1)`
` i=1 = 0.80`
` i=0.80 + 1 = 1.80`
` pi = icRT`
` = 1.80 xx 0.5 xx 0.0821 xx 300`
` = 22.167 ` atm