A `0.01m` aqueous solution of `K_(3)[Fe(CN)_(6)]` freezes ar `-0.062^(@)C`. What is the apparent percentage of dissociation? `[K_(f)` for water `= 1.86]`

Answer

0.777

Explanation

`(Delta T_(f))cal = 1.86 xx 0.01 = 0.0186`
` i= (0.062)/(0.0186) = 3.33`
`K_(3) [Fe(CN)_(6)] hArr 3K^(+) + [Fe(CN)_(6)]^(3-)`
`{:(,"Initial",1,0,0),(,"After dissociation",1-alpha , 3alpha , alpha//2):}`
` i= (1+3alpha)/(1) = 3.33`
`therefore " "alpha = 77.7%`