Calculate the molarity of each of the following solutions `:`
`a. 30g` of `Co(NO_(3))_(2).6H_(2)O` in `4.3L` of solution
`b. 30mL` of `0.5 M H_(2)SO_(4)` diluted to `500mL`.

Explanation

Molar mass of `Co(NO_(3))_(2),6H_(2),O`
`= 58.93 + 2 xx 14 + 6 xx 16 + 6 xx 18`
= 290.93
Moles of `Co(NO_(3))_(2).6H_(2)O = (30)/(209.93) = 0,103 `
Molarity `= (01108)/(4.3)= 0.024 M`
(b) `M_(1)V_(1) = M_(2)V_(2)`
`0.5 xx 30 mL = M_(2) xx 500 mL`
`therefore " "M_(2)= (0.5 xx 30)/(500) = 0.03M`