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Calculate the (a) molality, (b) molartiy...

Calculate the `(a)` molality, `(b)` molartiy, and `(c)` mole fraction of `KI` if the density of `20% (` mass `//` mass `)` aqueous `KI` is `1.202 g m L^(-1)`.

Text Solution

Verified by Experts

20% solution of KI means 20 g of KI are present in 100 g of solution or 80 g of water.
Mass of KI = 20 g
Molar mass of KI =39+127 = 166
Moles of KI `= (20)/(166) = 1.120`
(a) Molality ` = (0.120)/(80) xx 1000 = 15m`
(b) Volume of solution `= (100)/(1.202) = 83.19 mL`
Molarity `= (0.120)/(83.19) xx 1000 = 1.44 M`
(c) Moles of KI = 0.120
Moles of `H_(2)O = (80)/(18) = 4.44`
`x_(KI) = (0.120)/(4.44 + 0.120) = 0.0263`
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