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A solution is obtained by mixing 300 g o...

A solution is obtained by mixing 300 g of 25% solution and 400 g of 40% solutionby mass. Calculate the mass percentage of solute in the resulting solution.

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300 g of 25% solution contains solute ` = (300 xx 25)/(100) = 75g`
400 g of 40% solution contains solute `= (400 xx 40)/(100) = 160 g`
Total solute `= 75+160 =235 g`
Total solution ` = 300+400 = 700 g`
% of solute in the final solution ` = (235)/(700) xx 100 = 33.3%`
% of water in the final solution = 100 - 33.5 = 65.5%.
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