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The vapour pressure of water is 12.3 kPa...

The vapour pressure of water is `12.3 kPa` at `300 K`. Calculate vapour pressure of `1` molal solution of a solute in it.

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Verified by Experts

Mole fraction of solute `= (1)/(1+1000//18) = 0.0177`
`(p^(@) - p_(A))/(p^(@)) = 0.0177`
` (12.3 - p_(A))/(12.3) = 0.0177`
`p_(A) = 12.08 Kpa`
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