A `5%` solution (by mass) of cane sugar in water has freezing point of 271 K. Calculate the freezing point of a 5% glucose (by mass) in water. The freezing point of pure water is 273.15 K.

Explanation

For cane sugar , ` Delta_(f) = 273.15-271.0 = 2.15^(@)`
`K_(f) = (2.15 xx 100 xx 342)/(1000 xx 5)`
For glucose solution ,
`DeltaT_(f) = (14.706 xx 1000 xx 5)/(100 xx 180) = 4.058 K`
`therefore ` Freezing point `= 273.15 - 4.085 = 269.07 K`.