Vapour pressure of water at 293 K is 17.535 mm Hg. Calculate the vapour pressure of water at 293 K when 25 g of glucose is dissoved in 450 g of water.

Explanation

`(p^(@) - P)/(p^(@)) = x_(2) ~~ (W_(B) - M_(A))/(M_(B) - W_(A))`
`(17.535 - p)/(17.535) = (25 xx 18)/(180 xx 450)`
`(17.535 - p)/(17.535 ) = 5.56 xx 10^(-3)`
`therefore " "17.535 - p = 0.0975`
` p = 17.438` mm Hg