Henry's law constant for the molality of methane in benzene at 298 K is `4.27xx10^(5)mm` Hg. Calculate the solubility of methane in benzene at 298 K under 760 mm Hg.

Explanation

`p = k xx c`
760 mm ` = 4.26 xx 10^(5) mm xx C`
`therefore " " C = (760)/(4.25 xx 10^(5)) = 178 xx 10^(-5)`
or `" "1.78 xx 10^(-3)`