If observed value of the colligative property is more than the normal value of same property then Van't Hoff factor is more than one.

Answer

To solve the question, we need to analyze the relationship between the observed value of a colligative property, the theoretical value of that property, and the Van't Hoff factor (i). Here’s a step-by-step breakdown of the solution:

### Step 1: Understand Colligative Properties
Colligative properties are properties that depend on the number of solute particles in a solution, not on the nature of the solute. Examples include boiling point elevation, freezing point depression, vapor pressure lowering, and osmotic pressure.

### Step 2: Define Van't Hoff Factor (i)
The Van't Hoff factor (i) is defined as the ratio of the observed colligative property to the theoretical colligative property. Mathematically, it can be expressed as:
\[ i = \frac{\text{Observed colligative property}}{\text{Theoretical colligative property}} \]

### Step 3: Analyze the Given Statement
The question states that if the observed value of the colligative property is greater than the normal (theoretical) value, then the Van't Hoff factor is greater than 1.

### Step 4: Set Up the Inequality
If the observed value is greater than the theoretical value, we can express this as:
\[ \text{Observed colligative property} > \text{Theoretical colligative property} \]

### Step 5: Substitute into the Van't Hoff Factor Equation
Substituting this into the Van't Hoff factor equation:
\[ i = \frac{\text{Observed colligative property}}{\text{Theoretical colligative property}} > 1 \]

### Step 6: Conclusion
Since the inequality shows that the Van't Hoff factor (i) is greater than 1, we conclude that the statement is true.

### Final Answer
The statement is **True**.

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