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For 100% dissociation of K(4) [Fe(CN)(6)...

For 100% dissociation of `K_(4) [Fe(CN)_(6)]`, Van't Hoff factor i=……………. .

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To find the Van't Hoff factor (i) for the 100% dissociation of \( K_4[Fe(CN)_6] \), we can follow these steps: ### Step 1: Understand the Dissociation The compound \( K_4[Fe(CN)_6] \) dissociates completely into its constituent ions. The dissociation can be represented as: \[ K_4[Fe(CN)_6] \rightarrow 4K^+ + [Fe(CN)_6]^{4-} \] ### Step 2: Count the Number of Ions Produced From the dissociation equation, we can see that: ...
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