Calculate the boiling point of a 1M aqueous solution (density 1.04 g `Ml^(-1)`) of Potassium chloride `(K_(b) " for water " =0.52 K kg "mol"^(-1)," Atomic masse " : K=39u, CI=39.9u)` Assume, Potassium chloride is completely dissociated in solution.

Explanation

`NaCl to Na^(+) + Cl^(-1)`
I = 2
`Delta T_(b) = I xx K_(b) xx m`
` = 2 xx (0.52 Km^(-1)) x x(1m)`
` = 1.04 K`
Boiling point of solution = 373+1.04 = 374.04 K .