Calculate the molar mass of a substance `1 g` of which when dissolved in `100 g ` of water gave a solution boiling at `100.1^(@)C` at a pressure of 1 atm `(K_(b)` for water `= 0.52 K kg mol^(-1))`

Explanation

`M_(B) = (K_(b) xx 1000 xx w_(B))/(W_(A) xx Delta T_(B))`
`K_(b) = 0.52 Km^(-1) , w_(B) = 1.3g, w_(A) = 169 g`
`Delta T_(b) = 100.025 - 100 = 0.025 K`
`M_(B) = (0.52 xx 1000 xx 1.3)/(169 xx 0.025)`
` = 160 g mol^(-1)`