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Benzene and toluene form nearly ideal so...

Benzene and toluene form nearly ideal solution. If at `300K P_("bentezne")=103.01 `mm.
(i) Calculate the vapour pressure of a solution containing `0.6` mole fraction of toluene.
(ii) Calculate the mole fraction of toluene in the vapour form for this composition of liquid.

Text Solution

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Let the weight perecent of toluene in solution is x. This means x g of toluene are present in 100 g of solution .
Wt . Of toluene = x g .
Wt. of benzene = (100- x) g
Mol.wt of benzene `(C_(6)H_(6))` = 78
Mol.wt of toluene `(C_(6)H_(5)CH_(3))` = 92
Now `" "(n_(t))/(n_(t) + n_(b)) = 0.5`
`((x)/(92))/((x)/(92) + ((100-x))/(78)) = 0.5`
`((x)/(92))/((78x + 92(100-x))/(92xx78)) = 0.5`
`(x)/(92) xx (92 xx78)/(78x +92(100-x)) = 0.5`
`78x = 39 x + 4600 - 46x`
`85 x = 4600`
`therefore " " x =54.1`
`therefore" "` Wt% of toluene = 54.1
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