The depression in freezing expected for 0.6 m `Al_(2)(SO_(4))_(3)` solution will be 'n' times compared with 0.2 m `Na_(2)SO_(4)` solution. The value of n is.

Answer

5

Explanation

`Delta T_(f) ik_(f) xx m`
For 0.6 m `Al_(2) (SO_(4))_(3)`,
`DeltaT _(f) = 5 xx k_(f) xx 0.6 = 3.0 k_(f)(i=5)`
For 0.2 m `Na_(2)SO_(4)`
`Delta T_(f) = 3 xx K_(f) xx 0.2 = 0.6 K_(f) (i=3)`
Thus `Delta T_(f)` for `Al_(2)(SO_(4))_(3)` solution is 5 times that for `Na_(2)SO_(4)` solution.