Home
Class 12
CHEMISTRY
29.2% (w/w) HCl stock solution has a den...

29.2% (w/w) HCl stock solution has a density of 1.25 g `mL^(-1)`. The molecular weight of HCl is 36.5 g `"mol"^(-1)`. The volume (mL) of stock solution required to prepare a 200mL solution of 0.4 M HCl is :

Text Solution

Verified by Experts

The correct Answer is:
8
Mass of HCl = 29.2 g
Volume of solution `= (100g)/(1.25) = 80 mL`
Molarity of solution `= ( g mol)/(" Volume of solution") xx 1000`
` = (29.2//36.5)/(80) xx 1000 = 10 M`
Using `M_(1)V_(1) = M_(2)V_(2)`
`10 xx V_(1) = 200 xx 0.4`
`therefore " "V_(1) = (200 xx 0.4)/(10) = 8`
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    MODERN PUBLICATION|Exercise UNIT PRACTICE TEST|14 Videos

  • SOLUTIONS

    MODERN PUBLICATION|Exercise COMPETITION FILE (MARTIX MATCH TYPE QUESTIONS)|2 Videos

  • SOLID STATE

    MODERN PUBLICATION|Exercise UNIT PRACTICE TEST|13 Videos

  • SURFACE CHEMISTRY

    MODERN PUBLICATION|Exercise COMPETITION FILE (OBJECTIVE TYPE QUESTIONS) (MATCHING LIST TYPE QUESTIONS)|2 Videos

Similar Questions

Explore conceptually related problems

29.2% (w//w) HCl stock, solution has a density of 1.25 g mL^(-1) . The molecular weight of HCl is 36.5 g mol^(-1) . The volume (mL) of stock solution required to prepare a 200 mL solution of 0.4 M HCl is :

The answer to each of the following questions is a single digit integer, ranging from 0 to 9. If correct answers to the question number A,B,C and D (say) are 4,0,9 and 2 respectively, then correct darkening of bubbles should be as shown on the side. (D) 29.2 (w/w) HCl stock solution has a density of 1.25 g mL^(-1) . The molecular weight of HCl is 36.5 g mol^(-1) . The volume (mL) of stock solution required to prepare a 200 mL solution of 0.4 M HCl is ..........................

29.2% (w/w) HCl stock solution has a density of 1.25 g mL^(-1) . The molecular weight of HCl is 36.5 g "mol"^(-1) . Find the Volume (V)(mL) of stock solution required to prepare a 500 mL solution of 0.4 M HCl. Report your answer as V//5

29.2% (W//W) HCl stock solution has density of 1.25g mL^(-1) . The molar mass of HCl is 36.5g mol^(-1) . The volume (mL) of stock solution required to prepare a 200 mL solution of 0.4M HCl is

29.2 % (W//W) HCl stock solution has a density of 1.25 "g mL"^(-1) . The molecular mass of HCl is 36.5 g mol^(1) . What is the volume (mL) of stock required to prepare 200 mL of solution of 0.4 M HCl ?

29.2% (W/W) HCI stock solution has a density of 1.25 g mL^(-1) . The molecular mass of HCI is 36.5 g mol^(-1) Calculate the volume (mL) of stock solution required to prepare 200 mL of 0.4 M HCI

An aqueous solution has a density of 1. 37 g//ml . If molecular wt of solute is 68.5 g//mol , then calculate molarity of solution.

Calculate the volume of 0.015 M HCl solution required to prepare 250 mL of a 5.25 xx 10^(-3) M HCl solution

The density of 2.0 M solution of a solute is 1.2 g mL^(-1) . If the molecular mass of the solute is 100 g mol^(-1) , then the molality of the solution is