`MX_(2)` dissociates into `M^(2+)` and `X^(-)` ions in an aqeous solution, with a degree dissociation `(alpha)` of 0.5. The ratio of the observed depression of freezing point of the aqueous solution to the value of the depression of freezing point in the absence of ionic dissociation is

Answer

2

Explanation

`MX_(2) hArr M^(2+) + 2X^(-)`
If `alpha` is the degree of dissociaiton.
` 1 -alpha " " alpha" " 2 alpha`
Total moles after dissociation.
` =1 - alpha + alpha + 2 alpha = 1 +2alpha`
` I = (1+2a)/(1) = 1 + 2alpha`
` = 1 + 2 xx 0.5 = 2`