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0.05 M NaOH solution offered a resistanc...

0.05 M NaOH solution offered a resistance of 31.6 ohm in a conductivity cell at 298 K . If the area of the plates of the conductivity cell is `3.8 cm^(2)` and distance between them is 1.4 cm , calculate the molar conductivity of the sodium hydroxide solution .

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To calculate the molar conductivity of the sodium hydroxide (NaOH) solution, we can follow these steps: ### Step 1: Calculate the Conductivity (κ) The conductivity (κ) of the solution can be calculated using the formula: \[ \kappa = \frac{1}{R} \] where \( R \) is the resistance of the solution. ...
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MODERN PUBLICATION-ELECTROCHEMISTRY -UNIT PRACTICE TEST
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