Select the equivalent conductivity of `1.0 M H_(2)SO_(4)`, if its conductivity is `0.26 ohm^(-1) cm^(-1)`:

Explanation

Conductivity = `26 xx 10^(-2) ohm^(-1) cm^(-1)`
Concentration = 1 ` M H_(2) SO_(4) = 98` g/ litre
Equivalent weight of `H_(2) SO_(4) = 49`
Gram equivalents per litre = `(98)/(49) = 2`
Equivalent conductivity = `( kappa xx 1000)/(C) = (26 xx 10^(-2) xx 1000)/(2)`
`= 130 ohm^(-1) cm^(2) "equiv"^(-1)`