A potential difference of 20 V applied to the ends of a column of 0.1 M `AgNO_(3)` solution 4 cm in diameter and 12 cm in length gave a current of 0.20 amperes . Calculate
(i) conductivity and
(ii) molar conductance of the solution .

Explanation

To solve the problem step-by-step, we will calculate the conductivity and molar conductance of the given `AgNO3` solution.

### Given Data:
- Potential difference (V) = 20 V
- Current (I) = 0.20 A
- Concentration (C) = 0.1 M
- Diameter of the column (d) = 4 cm
- Length of the column (L) = 12 cm
...