The conductivity of a solution of AgCl at 298 K is found to be `1.382xx10^(-6)Omega^(-1)cm^(-1)` the ionic conductance of `Ag^(+)` and `Cl^(-)` at infinite dilution are `61.9Omega^(-1)cm^(2)col^(-1)` ad `76.3Omega^(-1)cm^(2)mol^(-1)` respectively the solubility of AgCl is

Explanation

`Lambda_(m)^(@) (AgCl) = lambda^(@) (Ag^(+)) + lambda^(@) (Cl^(-))`
= `62.0 + 76.3`
`= 138.3 S cm^(2) mol^-1`
`kappa = 1.386 xx 10^(-6) S cm^(-1)`
`Lambda_(m)^(@) = (kappa xx 1000)/(M) = (kappa xx 1000)/("Solubility")`
`therefore " "` Solubility = `(kappa xx 1000)/(Lambda_(m)^(@))`
`= (1.386 xx 10^(-6) xx 1000)/(138.3)`
= `1.0 xx 10^(-5) mol L^(-1)`
`1.0 xx 10^(-5) xx 143.5 g L^-1`
`= 1.435 xx 10^(-3) g L^(-1)`