At what concetration of `Ag^(2+)` ions, will the electrode have a potential of 0.0 V?

Explanation

For the reduction electrode reaction of silver ,
`E_(Ag^(+)|Ag)^(@) = E_(Ag^(+)|Ag)^(Theta) - ((0.059))/(1) "log" ([Ag])/([Ag^(+)])`
`E_(Ag^(+) |Ag) = 0 , E_(Ag^(+) |Ag)^(Theta) = 0.80` ,
`[Ag^(+)] = ? , [Ag] =1`
`therefore " " 0 = 0.80 - 0.059 "log " ([Ag])/([Ag^(+)])`
or `0.059 log [Ag^(+)] = -0.80`
or `log [Ag^(+)] = (-0.80)/(0.059) = - 13.559`
`[Ag^(+)] = 2.76 xx 10^(-14) M`