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The value of DeltaG^(@) in the Daniell c...

The value of `DeltaG^(@)` in the Daniell cell has been found to be -212.3 kJ at `25^(@)C`. Calculate equilibrium constant for the reaction.

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`Delta G^(Theta) = - RT ln K_c`
Here `DeltaG^(Theta) = -212.3 kJ = -212300 J , T = 298 K `
`R = 8.314 JK^(-1) mol^(-1)`
`- 212300 J = - (8.314 JK^(-1) mol^(-1)) xx (298 K ) ln K_(c)`
or `ln K_(c) = (212300)/(8.314 xx 298) = 85.69`
or `K_(c) = 1.64 xx 10^(37)`.
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