(a)For the reaction :
`2AgCl (s) + H_(2)(g) ` (1 atm) ` to 2 Ag(s) + 2H^(+) (0.1M) + 2Cl^(-) (0.1M) , DeltaG^(@) = -43600J` at `25^(@)`C.
Calculate the e.m.f. of the cell . [log `10^(-n) = -n`].
(b) Define fuel cell and write its two advantages.

Explanation

`Delta G^(@) = - n FE_(cell)^(@)`
`- 43600 = - 2 xx 96500 xx E_(cell)^(@)`
`E_(cell)^(@) = (43600)/(2 xx 96500) = 0.226 V `
`2 Ag Cl (s)+ H_(2) (g) (1 atm ) to 2 Ag (s) + 2 H^(+) (0.1 M) + 2 Cl^(-) (0.1 M)`
`E_(cell) = E_(cell)^(@) - (0.059)/(2)"log" ([H^(+)]^(2) [Cl^(-)]^(2))/([H_(2) (g)])`
`= 0.266 - 0.0295 log ((0.1)^(2) xx (0.1)^(2))/(1)`
`0.226 - 0.0295 xx log 10^(-4)`