A solution of `CuSO_(4)` is electroysed for 10 minutes with a current of 1.5 amperes. What is the mass of copper deposited at the cathode ?
(Molar mass of `Cu=63.5 g//mol)`

Explanation

Current strength (I) = 1. 5 A
Time (t) = 10 min = `10 xx 60 = 600` s
Quantity of electricity passed = `I xx t`
= `(1.5A) xx (600 s)`
`= 900 C (as = C`
Copper is deposited as :
`Cu^(2+) + 2e^(-) to Cu (s)`
2 mol of electrons or `2 xx 96500 C` of current deposit copper
`63.56 g`
900 C of current will deposit copper = `(63.56)/(2 xx 96500) xx 900`
`0.296 ` g .