How many minutes it would take to reduce 0.20 mol of `Cu^(2+)` to Cu using a current of 10 A .

Explanation

To solve the problem of how many minutes it would take to reduce 0.20 mol of \(Cu^{2+}\) to Cu using a current of 10 A, we can follow these steps:

### Step 1: Understand the electrolysis process
The reduction of \(Cu^{2+}\) to Cu involves the transfer of electrons. The half-reaction for this process is:
\[ Cu^{2+} + 2e^- \rightarrow Cu \]
This indicates that 2 moles of electrons are required to reduce 1 mole of \(Cu^{2+}\).
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