How many coulombs are required for the oxidation of `1 mol` of `H_(2)O` to `O_(2)`?

Explanation

Oxidation of `H_(2)O` to `O_(2)`
` 2H_(2) O hArr 4 H^(+) + O_(2) + 4 e^(-)`
Oxidation of 2 mol of `H_2O` require = `4 xx 96500 C`
Oxidation of 1 mol of `H_2 O` requires = `2 xx 96500 C`
= `1.93 xx 10^(5)` C .