How many coulombs of electricity are required for the reduction of 1 mole of `MnO_(4)^(-)` to `Mn^(2+)` ?

Explanation

Reduction of 1 mol of `MnO_(4)^(-)` to `Mn^(2+)`
` MnO_(4)^(-) + 8 H^(+) + 5 e^(-) to Mn^(2+) + 4 H_(2) O`
Reduction of 1 mol of `MnO_(4)^(-)` requires = `5 xx 96500 C`
`= 4.825 xx 10^(5)` C .