How much charge in faraday is required for the reduction of 1 mole of `Cu^(2+)` ions to Cu ?

Explanation

Reduction of `Cu^(2+)` to Cu
`Cu^(2+) + 2e^(-) to Cu`
Reduction of 1 mol of `Cu^(2+)` requires = ` 2 xx 96500 C`
`= 1.93 xx 10^(5) C`.