In the electrolysis of acidulated water, it is desired to obtain 1.12 cc of hydrogen per second under STP condition. The current to be passed is:

Explanation

`2H^(+) + 2e^(-) to H_(2)`
1 mol of `H_(2)` or 22400 ec of `H_(2)` at STP requires = `2 xx 96500 C`
`therefore` 1ec of `H_(2)` to N.T.P. requires = `(2 xx 96500)/(22400) = 8.616` C
Now , `Q = I xx t`
`I = (Q)/(t) = (8.616)/(1 s)`
`= 8.616` ampere .