How many moles of mercury will be produced by electrolysing 1.0 M `Hg(NO_(3))_(2)` solution by a current of 2.0 A when passed for 3 hours ?

Explanation

`H^(2+) + 2 e^(-) to Hg`
Quantity of electricity passed = `I xx t` (sec )
`= 2.0 A xx 3.0 xx 60 xx 60`
`= 21600 C`
`2 xx 96500` C of electricity produce mercury = 1 mol
21600 C of electricity of produce mercury= `(1)/(2 xx 96500) xx 21600`
= `0.112` mol