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Calculate the e.m.f. of the cell in whic...

Calculate the e.m.f. of the cell in which the following reaction takes place :
`Ni(s) +2Ag^(+)(0.002 M)to Ni^(2+)(0.160 M)+2Ag(s)`
Given `E_(cell)^(@)`=1.05 v

Text Solution

Verified by Experts

`E_(cell) = E_(cell)^(Theta) - (0.059)/(2)"log" ([Ni^(2+)])/([Ag^(+)]^(2))`
`= 1.05 - (0.059)/(2) "log" (0.160)/((0.002)^(2))`
`= 1.05 - (0.059)/(2) xx 4.602`
`= 1.05 - 0.14 = 0.91` V .
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