Write the Nernst equation for the cell reaction in the Daniel cell. How will the `E_("cell")` be affected when concentration of `Zn^(+)` ions is increased?

Explanation

The cell reaction for Daniel cell is :
`Zn + Cu^(2+) to Zn^(2+) + Cu`
`E_(cell) = E_(cell)^(Theta) - (0.059)/(2) "log" ([Zn^(2+)])/([Cu^(2+)])`
`E_(Cell)` decreases when concentration of `Zn^(2+)` ions `[Zn^(2+)]` increases .