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The cell constant of a conductivity cell...

The cell constant of a conductivity cell

A

changes with change in concentration of electrolyte

B

changes with nature of the electrolyte

C

changes with change in time of measurement

D

remains constant for the cell.

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A conductivity cell is used to measure the conductance of electrolyte . It makes use of conductivity of water which does not contain any ions. The cell constant of conductivity cell is determined. If the cell constant is 0.40 cm^(-1) , the conductivity of 0.051 M NaCl solution having R=1850 ohm is equal to

A conductivity cell is used to measure the conductance of electrolyte . It makes use of conductivity of water which does not contain any ions. The cell constant of conductivity cell is determined. Calculate alpha of CH_(3)COOH if Delta^(oo)._(m) for HCl, NaCl, CH_(3)COOHNa are 426,126,91 S cm^(2) mol^(-1) , respectively, and wedge_(m)=14.4 S cm^(2) mol^(-1) at 0.015 M concentration.

The conductance of a solution of an electrolyte is equal to that of its specific conductance The cell constant of the conductivity cell is equal to

The resistance of 0.01 M NaCl solution at 25°C is 200 ohm.The cell constant of the conductivity cell used is unity. Calculate the molar conductivity of the solution.

(a) What are the two classifications of batteries ? What is the difference between them ? (b) The resistanc of 0.01 M NaCl solution at 25^(@)C is 200Omega. The cell constant of the conductivity cell is unity. Calculate the molar conductivity of the solution.

The resistance of 0.01 M AgNO_(3) solution dipped in a conductivity cell at 25^(@) C was 1412 ohms . If the molar conductivity of this solution 132.6 ohm^(-1) cm^(2) mol^(-1) , what is the cell constant of the conductivity cell ?

A 0.05 M NaOH solution offered a resistance of 31.6 Omega in a conductivity cell at 298 K. If the cell constant of the conductivity cell is 0.367 cm^(-1) , find out the specific and molar conductance of the sodium hydroxide solution.

Knowledge Check

  • A conductivity cell is used to measure the conductance of electrolyte . It makes use of conductivity of water which does not contain any ions. The cell constant of conductivity cell is determined. If the cell constant is 0.40 cm^(-1) , the conductivity of 0.051 M NaCl solution having R=1850 ohm is equal to

    A
    `1.08xx10^(-4)S cm^(-1)`
    B
    `4.32 xx 10^(-4) S cm^(-1)`
    C
    `2.16xx10^(-4) S cm^(-1)`
    D
    `5.04xx10^(-5) S cm^(-1)`

  • A conductivity cell is used to measure the conductance of electrolyte . It makes use of conductivity of water which does not contain any ions. The cell constant of conductivity cell is determined. Calculate alpha of CH_(3)COOH if Delta^(oo)._(m) for HCl, NaCl, CH_(3)COOHNa are 426,126,91 S cm^(2) mol^(-1) , respectively, and wedge_(m)=14.4 S cm^(2) mol^(-1) at 0.015 M concentration.

    A
    `0.037`
    B
    `0.018`
    C
    `0.37`
    D
    `0.18`

  • The conductance of solution of an electrolyte is equal to that of its specific conductance. The cell constant of the conductivity cell is equal to

    A
    Resistance
    B
    Faraday
    C
    Zero
    D
    Unity
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