Molar conductivity of a weak acid HA at infinite dilution is 345.8 `Scm^(2) mol^(-1)` calculate molar conductivity of 0.05 M HA solution

Molar conductivity of a weak acid HA at infinite dilution is 345.8 cm^(2) mol^(-) calculate molar conductivity of 0.05 M HA solution

The molar conductance of acetic acid at infinite dilution is 390.7 S cm^(2) mol^(-1) . Calculate the molar conductance of 0.01 M acetic acid solution , given that the dissociation constant of a acetic acid is 1.8 xx 10^(-5) .

A weak monobasic acid is 5% dissociated in 0.01 mol dm^(-3) solution. The limiting molar conductivity at infinite dilution is 4.00xx10^(-2) ohm^(-1) m^(2) mol^(-1) . Calculate the conductivity of a 0.05 mol dm^(-3) solution of the acid.

The specific conducitivity of a 0.5 M aq. Solution of monobasic acid HA at 27^(@)"C" is 0.006 "Scm"^(1) . It’s molar conductivity at infinite dilution is 200 S "cm"^(2)"mol"^(-1) . Calculate osmotic pressure (in atm) of 0.5 M HA(aq) solution at 27^(@)"C" . Given R =0.08"L""-atm"//"K""-mol"

The molar conductivity of a 1.5 M solution of an electrolyte is found to be 138.9 S cm^(2) mol^(-1) . Calculate the conductivity of this solution.

Molar conductivity of a 1.5 m solustion of an electrolyte is found to be 138.9 S cm^(2) mol^(-1) . Calculate the conductivity of this solution.