Home
Class 12
CHEMISTRY
The equilibrium constant (K) for the rea...

The equilibrium constant (K) for the reaction
`Cu(s)+2Ag^(+) (aq) rarr Cu^(2+) (aq)+2Ag(s)`, will be
[Given, `E_(cell)^(@)=0.46 V`]

Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    MODERN PUBLICATION|Exercise HOTS (HIGHER ORDER THINKING SKILLS)|18 Videos
  • ELECTROCHEMISTRY

    MODERN PUBLICATION|Exercise COMPETITION FILE (OBJECTIVE TYPE QUESTIONS) (MULTIPLE CHOICE QUESTIONS )|35 Videos
  • ELECTROCHEMISTRY

    MODERN PUBLICATION|Exercise REVISION EXERCISES OBJECTIVE QUESTIONS Short Answer Questions|46 Videos
  • D AND F-BLOCK ELEMENTS

    MODERN PUBLICATION|Exercise UNIT PRACTICE TEST|12 Videos
  • GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS

    MODERN PUBLICATION|Exercise COMPETION FILE (Integer Type Numerical Value Type Questions)|5 Videos

Similar Questions

Explore conceptually related problems

The equilbrium constant for the reaction : Cu + 2 Ag^(+) (aq) rarr Cu(2+) (aq) +2 Ag, E^@ = 0. 46 V at 299 K is

Calculate the equilibrium costant log (K_(c)) for the reaction Zn(s)+Cu^(2+)(aq)rarrZn^(2+)(aq)+Cu(s) [Given E_(cell)^(2)=1.1 V ]

The equilibrium constant (K) for the reaction Fe^(2+)+(aq)Ag^(+)(aq)toFe^(3+)(aq)+Ag(s) will be Given E^(@)(Fe^(3+)//Fe^(2+))=0.77V, E^(@)(Ag^(+)//Ag)=0.80V

Calculate equilibrium constant for the reaction at 25^(@)C Cu(s)+2Ag^(+)(aq) hArr Cu^(2+)(aq)+2Ag(s) E^(@) value of the cell is 0.46 " V " .

Given the equilibrium constant : K_(c) of the reaction : Cu(s) + 2Ag^(+)(aq) rightarrow Cu^(2+) (Aq) + 2Ag(s) is 10xx10^(15) , calculate the E_(cell)^(@) of this reaction at 298K . ([2.303 (RT)/(Ft) at 298K = 0.059V])

Given the equilibrium constant : K_(C) of the reaction: Cu(s) + 2Ag^(+)(aq) to Cu^(2+) + 2Ag(s) is 10xx 10^(15) , calculate the E_("cell")^(ө) of this reaction at 298 K [2.303(RT)/(F) at 298 K = 0.059V]

Select the correct statement(s) for the given relation Cu(s)+2Ag^(+)(aq)rarrCu^(2+)(aq)+2Ag(s)

The equilibrium constant for the cell Cu(s)+2Ag^+(aq)rarrCu^(2+)(aq)+2Ag(s) ,at 298K is [Given, E_((Ag)^+/(Ag))^o=0.8V and E_((Cu)^(2+)/(Cu))^o=0.34V ]

Calculate the equilibrium constant of the reaction : Cu(s)+2Ag(aq) hArrCu^(2+)(aq) +2Ag(s) E^(c-)._(cell)=0.46V