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If E(Fe^(2+))^(@)//Fe = -0.441 V and E...

If `E_(Fe^(2+))^(@)//Fe = -0.441 V`
and `E_(Fe^(3+))^(@)//Fe^(2+) = 0.771 V`
The standard `EMF` of the reaction
`Fe+2Fe^(3+) rarr 3Fe^(2+)`
will be:

A

`1.653`

B

`1.212 V`

C

`0.111`

D

`0.330 V`

Text Solution

Verified by Experts

The correct Answer is:
B
`Fe^(2+) + 2e^(-) to Fe " " E_(1)^(Theta) = -0.414 V `
`Fe^(3+) + e^(-) to Fe^(2+) " " E_(2) ^(Theta) = 0.771 V `
The required equation can be obtained as :
`Fe to Fe^(2+) + 2e^(-)`
`2 Fe^(3+) + 2e^(-) to 2 Fe^(2+)`
`E_(cell)^(Theta) = E_(c)^(Theta) - E_(a)^(Theta) = 0.771 - (-0.441)`
`=1.212 V `
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