A constant current was passed through a solution of `AuCl_(4)^(c-)` ion between gold electrodes. After a period of `10.0 mi n`, the increase in the weight of cathode was `1.314g`. The total charge passed through solution is `(` atomic weight of `AuCl_(4)^(c-)=339)`

Options

A. 20 min 8s
B. 30 min 12s
C. 10 min 4s
D. 10 min 40s

Answer

C

Explanation

`Au^(3+) + 3e^(-) to Au`
197 g of Au is obtained by charge = `96500 xx 3 C `
1.234 g of Au is obtained by charge
`= (96500 xx 3 xx 1.234)/(197)`
`= 1813.4 C `
Now `I xx t = Q `
`3 xx t = 1813.4`
or t = `(1813.4)/(3) = 604 s`
= 10 min 4 s .