The solution of nickel sulphate in which nickel rod is dipped is diluted to 10 times. The potential of nickel.

Options

A. Decreases by 60 mV
B. Decreases by 30 mV
C. Decreases by 30 V
D. Increases by 30 mV

Answer

B

Explanation

Applying Nernst equation ,
` E = E^(@) - (0.059)/(2) "log" (1)/([Ni^(2+)])`
After dilution
`E = E^(@) - (0.059)/(2) "log" (1)/([Ni^(2+)] //10)`
`= E^(@) - (0.059)/(2) "log" (1)/([Ni^(2+)]) - (0.059)/(2) "log" 10`
`= E^(@) - (0.059)/(2) "log" (1)/([Ni^(2+)]) - 0.0295`
Hence ,reduction potential decreases by `0.0295 V = 29.5 m V = 30 mV `.