For the reduction of silver ions with copper metal, the standard cell potential was foound to be `+0.46 V` at `25^(@) C`. The value of standard Gibbs energy, `DeltaG^(@)` will be `(F = 96,500C mol^(-1))`:

Options

A. `-44.5` kJ
B. `-98.0` kJ
C. `-89.0` kJ
D. `-89.0 J`

Answer

C

Explanation

`Cu + 2 Ag^(+) to Cu^(2+) +2 Ag`
`Delta G^@ = - n FE^(@) = - 2 xx 96500 xx 0.46`
`= -88780 J = -89 kJ`.