A hydrogen gas electrode is made by dipping platinum wire in a solution of HCl or `pH = 10` and by passing bydrogen gas around the platinum wire at one atm pressure . The oxidation potential of electrode would be ?

Options

A. 0.118 V
B. 1.18 V
C. 0.059 V
D. 0.59 V

Answer

D

Explanation

`2 H^(+) + 2e^(-) to H_(2)`
`E (H^(+) , (1)/(2) H_(2)) = E^(@) - (0.059)/(2) "log" (1)/([H^(+)]^(2))`
`= 0 - (0.059)/(2) "log" (1)/((10^(-10))^(2))`
= `- (0.059)/(2) xx 20 = -0.59 V `
Oxidation potential = 0.59 V