The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is

Options

A. `6 xx 10^(23)`
B. `6 xx 10^(20)`
C. `3.75 xx 10^(20)`
D. `7.48 xx 10^(23)`

Explanation

To find the number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the relationship between current, charge, and time**:
The relationship is given by the formula:
\[ \text{Charge (Q)} = \text{Current (I)} \times \text{Time (t)} \]

2. **Substitute the given values**:
Here, the current \(I\) is 1 ampere and the time \(t\) is 60 seconds. Therefore, we can calculate the total charge:
\[ Q = 1 \, \text{A} \times 60 \, \text{s} = 60 \, \text{C} \]

3. **Determine the charge of a single electron**:
The charge of one electron is approximately:
\[ e = 1.6 \times 10^{-19} \, \text{C} \]

4. **Calculate the number of electrons**:
To find the total number of electrons (\(n\)), we can use the formula:
\[ n = \frac{Q}{e} \]
Substituting the values we have:
\[ n = \frac{60 \, \text{C}}{1.6 \times 10^{-19} \, \text{C/electron}} \]

5. **Perform the calculation**:
\[ n = \frac{60}{1.6 \times 10^{-19}} = 3.75 \times 10^{20} \, \text{electrons} \]

### Final Answer:
The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is \(3.75 \times 10^{20}\).

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