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For a cell involving one electron E(cell...

For a cell involving one electron `E_(cell)^(0)=0.59V` and 298K, the equilibrium constant for the cell reaction is:
[Given that `(2.303RT)/(F)=0.059V` at `T=298K`]

A

`1.0 xx 10^(30)`

B

`1.0 xx 10^(2)`

C

`1.0 xx 10^(5)`

D

`1.0 xx 10^(10)`

Text Solution

Verified by Experts

The correct Answer is:
D
`E_(cell)^(Theta) = (0.059)/(n) "log" K`
`0.59 = (0.059)/(1) log K`
or log `K = (0.59)/(0.059) = 10`
`K = 1 xx 10^(10)`
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