The reduction potential of a hydrogen electrode at `pH 10` at `298K` is : `(p =1` atm)

Options

A. 0.59 V
B. 0.00 V
C. `-0.59 V `
D. `-0.059 V `

Answer

C

Explanation

`H^(+) + e^(-) to H`
`E = E^(@) - (0.059)/(n) "log" (1)/([H^(+)])`
`= 0 - (0.059)/(1) pH = 0-0.059 xx 10 = -0.59 V `.