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Given E(cr^(3+)//Cr)^(0)=-0.74 V, E(Mn...

Given
`E_(cr^(3+)//Cr)^(0)=-0.74 V, E_(MnO_(4)//Mn^(2+))^(0)=1.51 cm`
`E_(Cr_(2)O_(7)^(2-)//Cr^(3+))^(0)=1.33 V, E_(Cl//Cl^(-))^(0)=1.36 V`
Based on the data given above, strongest oxidising agent will be:

A

`MnO_(4)^(-)`

B

`Cl^(-)`

C

`Cr^(3+)`

D

`Mn^(2+)`

Text Solution

Verified by Experts

The correct Answer is:
D

`Mn^(2+)` is the strongest oxidising agent because it has highest reduction potential value .
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Given E_("Cr_(2)O_(7)^(2-)//Cr^(3+))^(@)=1.33V,E_(MnO_(4)^(-)//Mn^(2+))^(@)=1.51V Among the following, the strongest reducing agent is E_(Cr^(3+)//Cr)^(@)=-0.74V^(x),E_(MnO_(4)^(-)//Mn^(2+))^(@)=1.51V E_(Cr_(2)O_(7)^(2-)//Cr^(3+))^(@)=1.33V,E_(Cl//Cl^(-))^(@)=1.36V Based on the data given above strongest oxidising agent will be

Given E_(Cr^(3+)//Cr^(@))= -O*74V , E_(MnO_(4)^(-)//Mn^(2+))^(@) = 1.51V E_(Cr_(2)O_(7)^(2-)//Cr^(3+))^(@) = 1.33V , E_(Cl//Cl^(-))^(@)= 1.36V Based on the given above , Strongest oxidising agent will be:

Give, E_(Cr^(3+)//Cr)^o =- 0. 74 V, E_(CnO_2^-)^o = 1.36 V, Based on the data given above, strongest oxidizing agent will be .

MODERN PUBLICATION-ELECTROCHEMISTRY -COMPETITION FILE (OBJECTIVE TYPE QUESTIONS) B MULTIPLE CHOICE QUESTIONS
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