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Two faraday of electricity is passed thr...

Two faraday of electricity is passed through a solution of `CuSO_(4)`. The mass of copper deposited at the cathode is: (at mass of Cu = 63.5 amu)

A

2 g

B

127 g

C

0 g

D

63.5 g

Text Solution

Verified by Experts

The correct Answer is:
D
`Cu^(2+) + 2e^(-) to Cu`
2 F of electricity deposit 1 mol of Cu
`therefore` Mass of Cu deposited = 63.5 g
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