The conductivity of `0.1 mol L^(-1) ` KCl solution is `1.41 xx 10^(-3) S cm^(-1)`. What is its molar conductivity (in `S cm^(2) mol^(-1)`) ?

Options

A. 375.6 K
B. 376. 3 K
C. 378.1 K
D. 380.3 K

Answer

A

Explanation

`alpha = (Lambda_(m)^(c))/(Lambda_(m)^(@))`
`= (240)/(420) = (12)/(21)`
`alpha = (i- 1)/(n -1) = (i-1)/(2 - 1) = (12)/(21)`
`i= (12)/(21) + 1 = (33)/(21)`
`Delta T_(b) = iK_(b) m`
`= (33)/(21) xx 0.52 xx 3 = 2.45` K
Boiling point of solution = `373.15 + 2.45`
`= 375.6 K`