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The pH of LHE in the following cell is :...

The `pH` of `LHE` in the following cell is `:`
`Pt, H_(2)(1atm)|H^(o+)(x M)||H^(o+)(0.1M)|H_(2)(0.1atm)Pt` E_(cell)=0.295V`.

A

` (-2.303 RT)/(F)`

B

`(2.303 RT)/(F)`

C

`(-2.303 RT)/(2F)`

D

`(2.303 RT)/(2F)`

Text Solution

Verified by Experts

The correct Answer is:
A
`E_(cell) = (2.303 RT)/(nF) "log" (C_(2))/(C_(1))`
`= (2.303 RT)/(1 xx F) "log" (0.1)/(1)`
`= - (2.303 RT)/(F)`
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